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<\/em><\/p>\n L\u00f4 k\u00e9p \u00e2m l\u00e0 g\u00ec?<\/em><\/p>\n B\u1ed1 s\u1ed1 b\u00f3ng \u1edf ph\u1ea7n tr\u00ean th\u01b0\u1eddng \u0111\u01b0\u1ee3c gi\u1edbi l\u00f4 \u0111\u1ec1 h\u1ecdc \u0111\u1eb7t cho c\u00e1i t\u00ean l\u00e0 B\u00f3ng d\u01b0\u01a1ng. \u0110\u1ecbnh ngh\u0129a v\u1ec1 2 b\u1ed9 s\u1ed1 b\u00f3ng n\u00e0y d\u1ef1a theo thuy\u1ebft \u00c2m d\u01b0\u01a1ng \u2013 Ng\u0169 h\u00e0nh. Ta c\u00f3 nh\u1eefng c\u1eb7p b\u00f3ng \u00e2m nh\u01b0 sau:<\/p>\n Theo \u0111\u00f3 th\u00ec 2 s\u1ed1 l\u00e0 b\u00f3ng \u00e2m c\u1ee7a nhau khi 2 ch\u1eef s\u1ed1 l\u00e0 b\u00f3ng \u00e2m c\u1ee7a nhau ho\u1eb7c 1 ch\u1eef s\u1ed1 gi\u1ed1ng nhau \u0111\u1ed3ng th\u1eddi s\u1ed1 c\u00f2n l\u1ea1i l\u00e0 b\u00f3ng \u00e2m c\u1ee7a nhau.<\/p>\n V\u00ed d\u1ee5:<\/p>\n 04 v\u00e0 01 l\u00e0 b\u00f3ng \u00e2m c\u1ee7a nhau do c\u00f3 c\u00f9ng s\u1ed1 0 \u0111\u1ed3ng th\u1eddi 4 v\u00e0 1 l\u00e0 b\u00f3ng \u00e2m c\u1ee7a nhau.<\/p>\n 32 v\u00e0 96 l\u00e0 b\u00f3ng \u00e2m c\u1ee7a nhau do 3 l\u00e0 b\u00f3ng \u00e2m c\u1ee7a 6 v\u00e0 2 l\u00e0 b\u00f3ng \u00e2m c\u1ee7a 9.<\/p>\n B\u1ed9 s\u1ed1 K\u00e9p \u00e2m<\/p>\n T\u1eeb \u0111\u1ecbnh ngh\u0129a v\u1ec1 b\u00f3ng \u00e2m ch\u00fang ta c\u00f3 b\u1ed9 s\u1ed1 k\u00e9p \u00e2m. K\u00e9p \u00e2m l\u00e0 b\u1ed9 c\u00e1c con s\u1ed1 m\u00e0 2 ch\u1eef s\u1ed1 c\u1ee7a n\u00f3 l\u00e0 b\u00f3ng \u00e2m c\u1ee7a nhau. B\u1ed9 k\u00e9p \u00e2m g\u1ed3m c\u00f3 c\u00e1c con s\u1ed1 d\u01b0\u1edbi \u0111\u00e2y:<\/p>\n 07, 70, 14, 41, 29, 92, 36, 63, 58, 85<\/p>\n Gi\u1ed1ng nh\u01b0 k\u00e9p l\u1ec7ch, k\u00e9p l\u1ec7ch \u00e2m \u0111\u01b0\u1ee3c gh\u00e9p t\u1eeb nh\u1eefng b\u1ed9 b\u00f3ng \u00e2m v\u1edbi nhau. T\u1ed5ng c\u1ed9ng t\u1eeb \u0111\u00f3 ta s\u1ebd c\u00f3 10 c\u1eb7p s\u1ed1 k\u00e9p l\u1ec7ch \u00e2m g\u1ed3m: 07, 70, 18, 81, 29, 92, 36, 63, 58, 85<\/p>\n <\/em><\/p>\n C\u00e1ch ch\u01a1i l\u00f4 k\u00e9p \u00e2m hi\u1ec7u qu\u1ea3<\/em><\/p>\n Tr\u00ean \u0111\u00e2y l\u00e0 nh\u1eefng kinh nghi\u1ec7m l\u00f4 \u0111\u1ec1 k\u00e9p \u0111\u01b0\u1ee3c d\u00f9ng \u0111\u1ec3 tham kh\u1ea3o nh\u01b0ng kh\u00f4ng ph\u1ea3i chu\u1ea9n 100%. V\u00ec v\u1eady, b\u1ea1n c\u00f3 th\u1ec3 tham kh\u1ea3o th\u00eam c\u00e1c b\u00e0i vi\u1ebft kh\u00e1c li\u00ean quan \u0111\u1ec3 ch\u1ecdn \u0111\u01b0\u1ee3c cho m\u00ecnh con s\u1ed1 ch\u00ednh x\u00e1c v\u00e0 ch\u1eafc ch\u1eafn nh\u1ea5t. Ch\u00fac b\u1ea1n may m\u1eafn.<\/p>\n<\/article>\n<\/div>\nB\u00f3ng \u00e2m<\/b><\/h2>\n
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K\u00e9p l\u1ec7ch \u00e2m l\u00e0 g\u00ec?<\/b><\/h2>\n
\u0110\u1ec1 v\u1ec1 k\u00e9p \u00e2m h\u00f4m sau \u0111\u00e1nh con g\u00ec?<\/b><\/h3>\n
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M\u1ed9t s\u1ed1 c\u00e1ch ch\u01a1i b\u1eaft k\u00e9p \u00e2m trong l\u00f4 l\u00f4 trong ng\u00e0y hi\u1ec7u qu\u1ea3<\/b><\/h2>\n
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k\u1ebft qu\u1ea3 soi c\u1ea7u cao c\u1ea5p<\/h3>\n